36x^2-60x+17=0

Solution for 36x^2-60x+17=0 equation:

36x^2-60x+17=0

a = 36; b = -60; c = +17;
Δ = b2-4ac
Δ = -602-4·36·17
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-24\sqrt{2}}{2*36}=\frac{60-24\sqrt{2}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+24\sqrt{2}}{2*36}=\frac{60+24\sqrt{2}}{72}
$